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The function f:R rarr R defined as f(x)=...

The function `f:R rarr R` defined as `f(x)=(3x^2+3x-4)/(3+3x-4x^2)` is :
(a) One to one but not onto
(b) Onto but not one to one
(c) Both one to one and onto
(d)Neither one to one nor onto

A

One ot one buty not onto

B

Onto but not one to one

C

Both one to one and onto

D

Neither one to one nor onto

Text Solution

AI Generated Solution

The correct Answer is:
To determine the nature of the function \( f(x) = \frac{3x^2 + 3x - 4}{3 + 3x - 4x^2} \), we need to analyze whether it is one-to-one (injective) and/or onto (surjective). ### Step 1: Set up the equation Let \( y = f(x) \): \[ y = \frac{3x^2 + 3x - 4}{3 + 3x - 4x^2} \] ### Step 2: Cross multiply to eliminate the fraction Multiply both sides by the denominator: \[ y(3 + 3x - 4x^2) = 3x^2 + 3x - 4 \] Expanding this gives: \[ 3y + 3xy - 4xy^2 = 3x^2 + 3x - 4 \] ### Step 3: Rearrange the equation Rearranging the equation, we get: \[ 4xy^2 - 3x^2 + (3y - 3)x + (3y + 4) = 0 \] ### Step 4: Analyze the quadratic in \( x \) This is a quadratic equation in \( x \). For the function to be one-to-one, this quadratic must have at most one solution for each \( y \). We can determine this by checking the discriminant of the quadratic equation. ### Step 5: Calculate the discriminant The discriminant \( D \) of a quadratic \( ax^2 + bx + c = 0 \) is given by: \[ D = b^2 - 4ac \] In our case: - \( a = 4y \) - \( b = 3y - 3 \) - \( c = 3y + 4 \) Thus, the discriminant is: \[ D = (3y - 3)^2 - 4(4y)(3y + 4) \] Calculating this: \[ D = 9y^2 - 18y + 9 - 48y^2 - 64y \] \[ D = -39y^2 - 82y + 9 \] ### Step 6: Analyze the discriminant For the function to be one-to-one, the discriminant must be less than or equal to zero: \[ -39y^2 - 82y + 9 \leq 0 \] This is a downward-opening parabola. We need to find the roots of the equation: \[ 39y^2 + 82y - 9 = 0 \] Using the quadratic formula: \[ y = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} = \frac{-82 \pm \sqrt{82^2 - 4 \cdot 39 \cdot (-9)}}{2 \cdot 39} \] Calculating the discriminant: \[ D' = 82^2 + 4 \cdot 39 \cdot 9 = 6724 + 1404 = 8128 \] Thus, the roots are: \[ y = \frac{-82 \pm \sqrt{8128}}{78} \] Since the discriminant is positive, there are two distinct real roots, indicating that the quadratic can change signs. ### Step 7: Conclusion about one-to-one Since the discriminant of the quadratic in \( x \) can be positive for some values of \( y \), the function is **not one-to-one**. ### Step 8: Check onto To check if the function is onto, we need to see if every real number \( y \) can be achieved by some \( x \). Since the discriminant can be zero or negative for some values of \( y \), it indicates that there are values of \( y \) that cannot be achieved, thus the function is **not onto**. ### Final Answer The function \( f(x) \) is neither one-to-one nor onto.
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