Home
Class 12
MATHS
Let z1=a+i b and z2=c+i d are two comple...

Let `z_1=a+i b` and `z_2=c+i d` are two complex number such that `|z_1|=r` and `R e(z_1z_2)=0` . If `w_1=a+i c` and `w_2=b+i d ,` then `|w_2|=r` (b) `|w_2|=r` `R e(w_1w_2)=0` (d) `I m(w_1w_2)=0`

A

`lm(w_1 barw_2)=0`

B

`lm ( barw_1w_2)=0`

C

`lm(((z_1+z_2)(z_2+z_3)(z_3+z_1))/(z_1.z_2.z_3))=0`

D

Re `(w_1/w_2)=0`

Text Solution

Verified by Experts

The correct Answer is:
A, B, C
Promotional Banner

Topper's Solved these Questions

  • COMPLEX NUMBERS

    VK JAISWAL ENGLISH|Exercise EXERCISE-3:COMPREHENSION TYPE PROBLEMS|8 Videos
  • COMPLEX NUMBERS

    VK JAISWAL ENGLISH|Exercise EXERCISE-4:MATCHING TYPE PROBLEMS|2 Videos
  • COMPLEX NUMBERS

    VK JAISWAL ENGLISH|Exercise EXERCISE-5 : SUBJECTIVE TYPE PROBLEMS|8 Videos
  • CIRCLE

    VK JAISWAL ENGLISH|Exercise Exercise - 5 : Subjective Type Problems|12 Videos
  • COMPOUND ANGLES

    VK JAISWAL ENGLISH|Exercise Exercise-5 : Subjective Type Problems|31 Videos

Similar Questions

Explore conceptually related problems

Let Z and w be two complex number such that |zw|=1 and arg(z)−arg(w)=pi//2 then

If z and w are two complex number such that |zw|=1 and arg (z) – arg (w) = pi/2, then show that overline zw = -i.

If z and w are two complex number such that |z w|=1 and a rg(z)-a rg(w)=pi/2 , then show that barz w=-i

Let z and w be two nonzero complex numbers such that |z|=|w| and arg(z)+a r g(w)=pidot Then prove that z=- barw dot

Let za n dw be two nonzero complex numbers such that |z|=|w|a n d arg(z)+a r g(w)=pidot Then prove that z=- bar w dot

If z_(1) = a + ib " and " z_(2) + c id are complex numbers such that |z_(1)| = |z_(2)| = 1 and Re (z_(1)bar (z)_(2)) = 0 , then the pair of complex numbers w_(1) = a + ic " and " w_(2) = b id satisfies :

For two complex numbers z_1&z_2 (a z_1+b z_1)(c z_2+d z_2)=(c z_1+bz_2)if(a , b , c , d in R):

Let z and w are two non zero complex number such that |z|=|w|, and Arg(z)+Arg(w)=pi then (a) z=w (b) z=overlinew (c) overlinez=overlinew (d) overlinez=-overlinew

If z 1 ​ =a+ib and z 2 ​ =c+id are complex numbers such that ∣z 1 ​ ∣=∣z 2 ​ ∣=1 and Re(z 1 ​ z 2 ​ ​ )=0, then the pair of complex numbers w 1 ​ =a+ic and w 2 ​ =b+id satisfy

Let z=x+iy and w=u+iv be two complex numbers, such that |z|=|w|=1 and z^(2)+w^(2)=1. Then, the number of ordered pairs (z, w) is equal to (where, x, y, u, v in R and i^(2)=-1 )