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Let matrix A=[(x,3,2),(1,y,4),(2, 2,z)]...

Let matrix `A=[(x,3,2),(1,y,4),(2, 2,z)], " if " xyz=2lambda and 8x+4y+3x=lambda+28`, then (adj A) A equals :

A

`[(lambda+1,0,0),(0,lambda+1,0),(0,0,lambda+1)]`

B

`[(lambda,0,0),(0,lambda,0),(0,0,lambda)]`

C

`[(lambda^(2),0,0),(0,lambda^(2),0),(0,0,lambda^(2))]`

D

`[(lambda+2,0,0),(0,lambda+2,0),(0,0,lambda+2)]`

Text Solution

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The correct Answer is:
B
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