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If the point (alpha, alpha^(4)) lies on ...

If the point `(alpha, alpha^(4))` lies on or inside the triangle formed by lines `x^(2)y+xy^(2)-2xy=0`, then the largest value of `alpha` is .

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To solve the problem, we need to determine the largest value of \( \alpha \) such that the point \( (\alpha, \alpha^4) \) lies on or inside the triangle formed by the lines given by the equation \( x^2y + xy^2 - 2xy = 0 \). ### Step-by-Step Solution: 1. **Rewrite the Equation**: The given equation is \( x^2y + xy^2 - 2xy = 0 \). We can factor this equation: \[ xy(x + y - 2) = 0 \] This gives us three cases: - \( x = 0 \) - \( y = 0 \) - \( x + y - 2 = 0 \) 2. **Identify the Lines**: The lines represented by the factors are: - \( x = 0 \) (the y-axis) - \( y = 0 \) (the x-axis) - \( x + y = 2 \) (a line with intercepts at (2, 0) and (0, 2)) 3. **Determine the Vertices of the Triangle**: The triangle formed by these lines has vertices at: - \( (0, 0) \) (intersection of \( x = 0 \) and \( y = 0 \)) - \( (2, 0) \) (intersection of \( y = 0 \) and \( x + y = 2 \)) - \( (0, 2) \) (intersection of \( x = 0 \) and \( x + y = 2 \)) 4. **Check if the Point Lies Inside the Triangle**: We need to check if the point \( (\alpha, \alpha^4) \) lies on or inside the triangle. This can be done by substituting the coordinates into the inequalities derived from the lines. 5. **Inequality from the Line \( x + y = 2 \)**: For the line \( x + y - 2 \geq 0 \): \[ \alpha + \alpha^4 - 2 \geq 0 \] Rearranging gives: \[ \alpha^4 + \alpha - 2 \geq 0 \] 6. **Finding Roots of the Polynomial**: We need to find the values of \( \alpha \) for which \( \alpha^4 + \alpha - 2 = 0 \). We can check some values: - For \( \alpha = 1 \): \[ 1^4 + 1 - 2 = 0 \quad \text{(satisfies)} \] - For \( \alpha = 2 \): \[ 2^4 + 2 - 2 = 16 + 2 - 2 = 16 \quad \text{(does not satisfy)} \] 7. **Analyze the Behavior of the Polynomial**: The polynomial \( \alpha^4 + \alpha - 2 \) is continuous and increases for \( \alpha > 1 \). Since it equals zero at \( \alpha = 1 \) and is positive for values greater than 1, we check if it becomes negative before reaching 2. 8. **Conclusion**: The largest value of \( \alpha \) for which \( \alpha^4 + \alpha - 2 \geq 0 \) is \( \alpha = 1 \). ### Final Answer: The largest value of \( \alpha \) such that the point \( (\alpha, \alpha^4) \) lies on or inside the triangle is: \[ \boxed{1} \]
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