Home
Class 12
MATHS
The parabola y=4-x^(2) has vertex P. It...

The parabola `y=4-x^(2)` has vertex P. It intersects x-axis at A and B. If the parabola is translated from its initial position to a new position by moving its vertex along the line `y=x+4`, so that it intersects x-axis at B and C, then abscissa of C will be :

A

3

B

4

C

5

D

8

Text Solution

Verified by Experts

The correct Answer is:
D
Promotional Banner

Topper's Solved these Questions

  • PARABOLA

    VK JAISWAL ENGLISH|Exercise Exercise-2 : One or More than One Answer is/are Correct|1 Videos

  • PARABOLA

    VK JAISWAL ENGLISH|Exercise Exercise-5 : Subjective Type Problems|2 Videos

  • MATRICES

    VK JAISWAL ENGLISH|Exercise Exercise-4 : Subjective Type Problems|5 Videos

  • PERMUTATION AND COMBINATIONS

    VK JAISWAL ENGLISH|Exercise Exercise-5 : Subjective Type Problems|13 Videos

Similar Questions

Explore conceptually related problems

The two parabolas y^(2)=4x" and "x^(2)=4y intersect at a point P, whose abscissas is not zero, such that

Find the equation of the lines joining the vertex of the parabola y^2=6x to the point on it which have abscissa 24.

Find the vertex, focus, directrix, axis and latus-rectum of the parabola y^2=4x+4ydot

Find the vertex, focus, directrix, axis and latus-rectum of the parabola y^2=4x+4ydot

The parabola y=-x^2+5x+6 is intersected by the line y=-1/2x+12 . What is the y-coordinate of the intersection closest to the x-axis?

The vertex of a parabola is the point (a,b) and latusrectum is of length l . If the axis of the parabola is along the positive direction of y-axis, then its equation is :

Find the equation of the parabola whose focus is (0,0) and the vertex is the point of intersection of the lines x+y=1 and x - y = 3.

If the vertex of the parabola y=x^(2) +x+c lies on x-axis, then the value of c, is

Find the equation of the parabola whose focus is at (0, 0) and vertex is at the intersection of the line x+y=1 and x-y=3 .

The vertex of the parabola y^(2) =(a-b)(x -a) is