Home
Class 12
MATHS
Set of values of x lying in [0, 2pi] sat...

Set of values of x lying in `[0, 2pi]` satisfying the inequality `|sin x | gt 2 sin^(2)` x contains

A

` (- (pi)/(6), (pi)/(6))`

B

`(-(pi)/(2), (pi)/(6)) cup ((pi)/(6), (5 pi)/(6)) `

C

`(-(pi)/(2), -(pi)/(6)) cup ((5 pi)/(6), pi ) `

D

`(-(pi)/(6),(pi)/(6)) cup ((5 pi)/(6), pi ) `

Text Solution

Verified by Experts

The correct Answer is:
D
Promotional Banner

Topper's Solved these Questions

  • TRIGONOMETRIC EQUATIONS

    VK JAISWAL ENGLISH|Exercise Exercise-2 : One or More than One Answer is/are Correct|11 Videos

  • TRIGONOMETRIC EQUATIONS

    VK JAISWAL ENGLISH|Exercise Exercise-3 : Comprehension Type Problems|3 Videos

  • STRAIGHT LINES

    VK JAISWAL ENGLISH|Exercise Exercise-5 : Subjective Type Problems|10 Videos

  • VECTOR & 3DIMENSIONAL GEOMETRY

    VK JAISWAL ENGLISH|Exercise Exercise-5 : Subjective Type Problems|13 Videos

Similar Questions

Explore conceptually related problems

The complete set of values of x, x in (-(pi)/(2), pi) satisfying the inequality cos 2x gt |sin x| is :

The set of values of x in (-pi, pi) satisfying the inequation |4"sin" x-1| lt sqrt(5) , is

The number of values of x in the interval [0, 3pi] satisfying the equation 2sin^2x + 5sin x- 3 = 0 is

The number of values of x in [0,2pi] satisfying the equation |cos x – sin x| >= sqrt2 is

The set of values of x in R satisfying the inequality x^(2)-4x-21 le 0 is

The number of values of x in the interval [0,5pi] satisfying the equation. 3sin^(2)x -7sinx + 2=0 is-

The number of values of x in [0, 4 pi] satisfying the inequation |sqrt(3)"cos" x - "sin"x|ge2 , is

The number of values of x in the interval [0, 3pi] satisfying the equation 3sin^(2)x-7sinx+2=0 is

The values of x in (0, pi) satisfying the equation. |{:(1+"sin"^(2)x, "sin"^(2)x, "sin"^(2)x), ("cos"^(2)x, 1+"cos"^(2)x, "cos"^(2)x), (4"sin" 2x, 4"sin"2x, 1+4"sin" 2x):}| = 0 , are

The number of values of x lying in the inteval (-2pi, 2pi) satisfying the equation 1+cos 10x cos 6x=2 cos^(2)8x+sin^(2)8x is equal to