Home
Class 12
MATHS
The number of points in interval [ - (pi...

The number of points in interval `[ - (pi)/(2) , (pi)/(2)], ` where the graphs of the curves ` y = cos x ` and ` y= sin 3x , -(pi)/(2) le x le (pi)/(2) ` intersects is

Text Solution

AI Generated Solution

The correct Answer is:
To find the number of points in the interval \([- \frac{\pi}{2}, \frac{\pi}{2}]\) where the graphs of the curves \(y = \cos x\) and \(y = \sin 3x\) intersect, we need to solve the equation: \[ \cos x = \sin 3x \] ### Step 1: Rewrite the equation Using the identity \(\sin 3x = \cos\left(\frac{\pi}{2} - 3x\right)\), we can rewrite the equation as: \[ \cos x = \cos\left(\frac{\pi}{2} - 3x\right) \] ### Step 2: Set up the cosine equation From the property of cosine, we know that if \(\cos A = \cos B\), then: \[ A = 2n\pi \pm B \] where \(n\) is any integer. Therefore, we can set up two cases: 1. \(x = 2n\pi + \left(\frac{\pi}{2} - 3x\right)\) 2. \(x = 2n\pi - \left(\frac{\pi}{2} - 3x\right)\) ### Step 3: Solve the first case For the first case: \[ x = 2n\pi + \frac{\pi}{2} - 3x \] Rearranging gives: \[ 4x = 2n\pi + \frac{\pi}{2} \] \[ x = \frac{2n\pi + \frac{\pi}{2}}{4} = \frac{n\pi}{2} + \frac{\pi}{8} \] ### Step 4: Solve for \(n = 0\) and \(n = -1\) 1. For \(n = 0\): \[ x = \frac{0 + \frac{\pi}{2}}{4} = \frac{\pi}{8} \] 2. For \(n = -1\): \[ x = \frac{-2\pi + \frac{\pi}{2}}{4} = \frac{-4\pi + \pi}{8} = \frac{-3\pi}{8} \] ### Step 5: Solve the second case For the second case: \[ x = 2n\pi - \left(\frac{\pi}{2} - 3x\right) \] Rearranging gives: \[ x = 2n\pi - \frac{\pi}{2} + 3x \] \[ -2x = 2n\pi - \frac{\pi}{2} \] \[ 2x = -2n\pi + \frac{\pi}{2} \] \[ x = -n\pi + \frac{\pi}{4} \] ### Step 6: Solve for \(n = 0\) and \(n = -1\) 1. For \(n = 0\): \[ x = 0 + \frac{\pi}{4} = \frac{\pi}{4} \] 2. For \(n = -1\): \[ x = \pi + \frac{\pi}{4} = \frac{5\pi}{4} \quad (\text{not in the interval}) \] ### Step 7: Collect all solutions The valid solutions from both cases in the interval \([- \frac{\pi}{2}, \frac{\pi}{2}]\) are: 1. \(x = \frac{\pi}{8}\) 2. \(x = -\frac{3\pi}{8}\) 3. \(x = \frac{\pi}{4}\) ### Conclusion Thus, the number of points where the curves intersect in the given interval is **3**. ---
Promotional Banner

Topper's Solved these Questions

  • TRIGONOMETRIC EQUATIONS

    VK JAISWAL ENGLISH|Exercise Exercise-4 : Matching Type Problems|2 Videos
  • STRAIGHT LINES

    VK JAISWAL ENGLISH|Exercise Exercise-5 : Subjective Type Problems|10 Videos
  • VECTOR & 3DIMENSIONAL GEOMETRY

    VK JAISWAL ENGLISH|Exercise Exercise-5 : Subjective Type Problems|13 Videos

Similar Questions

Explore conceptually related problems

Find the coodinates of the point of intersection of the curves y= cos x , y= sin 3x if -(pi)/(2) le x le (pi)/(2)

The area between the curves y=tanx,y=cotx and X-axis in (pi)/(6)le x le (pi)/(3) is

For -(pi)/(2)le x le (pi)/(2) , the number of point of intersection of curves y= cos x and y = sin 3x is

The area bounded by the curve y=cosx and y=sin 2x, AA x in [(pi)/(6), (pi)/(2)] is equal to

If 0 le x le pi/2 then

The number of points of intersection of the curves 2y =1 " and " y = "sin" x, -2 pi le x le 2 pi , is

Find the number of solutions of cos x =|1+ sin x |, 0 le x le 3 pi

Solve 2 cos^(2) x+ sin x le 2 , where pi//2 le x le 3pi//2 .

Area between the x -axis and the curve y=cosx , when 0 le x le 2pi is:

Find the coordinates of the points of intersection of the curves y=cosx , y=sin3x if-pi/2lt=xlt=pi/2