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Through the centroid of an equilateral t...

Through the centroid of an equilateral triangle, a line parallel to the base is drawn. On this line, an arbitrary point P is taken inside the triangle. Let h denote the perpendicular distance of P from the base of the triangle. Let `h_(1) and h_(2)` be the perpendicular distance of P from the other two sides of the triangle . Then :

A

`h=(h_(1)+h_(2))/(2)`

B

`h=sqrt(h_(1)h_(2))`

C

`h=(2h_(1)h_(2))/(h_(1)+h_(2))`

D

`h=((h_(1)+h_(2))sqrt(3))/(4)`

Text Solution

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The correct Answer is:
A
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