Home
Class 12
MATHS
The perimeter of a DeltaABC is 48 cm and...

The perimeter of a `DeltaABC` is `48 cm` and one side is `20 cm`. Then remaining sides of `DeltaABC` must be greater than : (a) `8 cm` (b) `9 cm` (c) `12 cm` (d) `4 cm`

A

8 cm

B

9 cm

C

12 cm

D

4 cm

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to find the minimum value of the remaining sides of triangle ABC given that the perimeter is 48 cm and one side is 20 cm. ### Step-by-Step Solution: 1. **Identify the given information**: - Perimeter of triangle ABC = 48 cm - One side (let's say side A) = 20 cm 2. **Set up the equation for the perimeter**: - Let the other two sides be B and C. - According to the perimeter, we have: \[ A + B + C = 48 \] - Substituting A = 20 cm: \[ 20 + B + C = 48 \] 3. **Solve for B + C**: - Rearranging the equation gives: \[ B + C = 48 - 20 = 28 \] 4. **Apply the triangle inequality**: - The triangle inequality states that the sum of the lengths of any two sides must be greater than the length of the third side. Therefore, we have: - \( A + B > C \) - \( A + C > B \) - \( B + C > A \) 5. **Substituting A = 20 cm into the inequalities**: - From \( A + B > C \): \[ 20 + B > C \quad \text{(1)} \] - From \( A + C > B \): \[ 20 + C > B \quad \text{(2)} \] - From \( B + C > A \): \[ B + C > 20 \quad \text{(3)} \] - We already know from step 3 that \( B + C = 28 \), so: \[ 28 > 20 \quad \text{(This is always true)} \] 6. **Rearranging inequalities (1) and (2)**: - From inequality (1): \[ C < 20 + B \] - From inequality (2): \[ B < 20 + C \] 7. **Express C in terms of B**: - From \( B + C = 28 \), we can express C as: \[ C = 28 - B \] - Substitute this into inequality (1): \[ 28 - B < 20 + B \] - Rearranging gives: \[ 28 - 20 < 2B \implies 8 < 2B \implies B > 4 \] 8. **Express B in terms of C**: - Similarly, substitute into inequality (2): \[ B < 20 + (28 - B) \] - Rearranging gives: \[ B < 48 - B \implies 2B < 48 \implies B < 24 \] 9. **Conclusion**: - From the inequalities derived: - \( B > 4 \) - \( B < 24 \) - Since B and C are interchangeable, we can conclude that both remaining sides must be greater than 4 cm. ### Final Answer: The remaining sides of triangle ABC must be greater than **4 cm**.
Promotional Banner

Topper's Solved these Questions

  • SOLUTION OF TRIANGLES

    VK JAISWAL ENGLISH|Exercise Exercise-2 : One or More than One Answer is/are Correct|14 Videos
  • SOLUTION OF TRIANGLES

    VK JAISWAL ENGLISH|Exercise Exercise-3 : Comprehension Type Problems|12 Videos
  • SEQUENCE AND SERIES

    VK JAISWAL ENGLISH|Exercise EXERCISE (SUBJECTIVE TYPE PROBLEMS)|21 Videos
  • STRAIGHT LINES

    VK JAISWAL ENGLISH|Exercise Exercise-5 : Subjective Type Problems|10 Videos

Similar Questions

Explore conceptually related problems

The perimeter of a parallelogram is 70cm. If one side measures 20 cm, find the measure of its adjacent side.

The perimeter of a parallelogram is 64 cm. If one side measures 18 cm, find the measure of its adjacent side

Find the perimeter of DeltaABC , if AP=12 cm

The hypotenuse of a right triangle is 26 cm long. If one of the remaining two sides is 10 cm long, the length of the other side is (a) 25 cm (b) 23 cm (c) 24 cm (d) 22 cm

Find the perimeter of an equilateral triangle with side 9cm.

The perimeter of a triangle is 16 cm. One ofthe sides is of length 6 cm. If the area of thetriangle is 12 sq. cm, then the triangle is

The length of a rectangle is 8 cm and its area is 48 c m^2dot The perimeter of the rectangle is (a)14 cm (b) 24 cm (c)12 cm (d) 28 cm

The perimeter of a triangle is 30cm. Two sides are 12cm and 10cm. What is the length of the third side of the triangle?

In Figure, the perimeter of A B C is (a) 30cm (b) 60cm (c) 45cm (d) 15cm

Find the perimeter of a triangle whose sides are 7 cm, 5.4 cm and 10.2 cm long,