Home
Class 12
MATHS
In a triangle ABC, side BC = 3, AC = 4 ...

In a triangle ABC, side BC = 3, AC = 4 and AB = 5. The value of `sinA+sin2B+sin3C` is equal to :

A

`(24)/(25)`

B

`(14)/(25)`

C

`(64)/(25)`

D

None

Text Solution

Verified by Experts

The correct Answer is:
B
Promotional Banner

Topper's Solved these Questions

  • SOLUTION OF TRIANGLES

    VK JAISWAL ENGLISH|Exercise Exercise-2 : One or More than One Answer is/are Correct|14 Videos

  • SOLUTION OF TRIANGLES

    VK JAISWAL ENGLISH|Exercise Exercise-3 : Comprehension Type Problems|12 Videos

  • SEQUENCE AND SERIES

    VK JAISWAL ENGLISH|Exercise EXERCISE (SUBJECTIVE TYPE PROBLEMS)|21 Videos

  • STRAIGHT LINES

    VK JAISWAL ENGLISH|Exercise Exercise-5 : Subjective Type Problems|10 Videos

Similar Questions

Explore conceptually related problems

In DeltaABC, a = 3, b = 4 and c = 5 , then value of sinA + sin2B + sin3C is

In DeltaABC, a = 3, b = 4 and c = 5 , then value of sinA + sin2B + sin3C is

In a triangle ABC, 2 ac sin (1/2(A-B + C)) =

If in a triangle ABC sin A = 4/5 and sin B = 12/13 , then sin C =

In triangle ABC, AB = AC = 15 cm and BC = 18 cm. Find : sin C

In a Delta ABC, if b=20, c=21and sin A =3/5, then the value of a is

In Delta ABC , if a = 3, b = 4 and sin B = 1 , find sin A

In an isosceles triangle ABC. AB = BC = 10 cm and BC = 18 cm . Find the value of : sin ^(2) B + cos ^(2) C

In triangle ABC , angle B = 90 ^(@) , AB = 40 , AC + BC = 80 , Find : sin A

In Delta ABC , If angle C = 3 angle A, BC = 27, and AB =48 . Then the value of AC is ______