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If |veca|=2, |vecb|=5 and veca*vecb=0, ...

If `|veca|=2, |vecb|=5 and veca*vecb=0`, then `veca xx (vecaxx(vecaxx(vecaxx(vecaxx(veca xx vecb)))))` is equal to :

A

`64veca `

B

`64vecb`

C

`-64veca`

D

`-64vecb`

Text Solution

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The correct Answer is:
D
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