If n=16 in plant cell, then how many bivalents in metaphase-I of meiosis are possible ?
(a) 32 bivalents
(b) 16 tetravalents
(c) 16 bivalents
(d) 32 bivalents

Options

A. 32 bivalents
B. 16 tetravalents
C. 16 bivalents
D. 32 bivalents

Answer

To determine the number of bivalents in metaphase-I of meiosis when n=16 in a plant cell, we can follow these steps:

### Step-by-Step Solution:

1. **Understand the term 'n':**
- The term 'n' refers to the haploid number of chromosomes. In this case, n = 16 means that there are 16 chromosomes in the haploid set.

2. **Determine the diploid number (2n):**
- The diploid number (2n) is twice the haploid number. Therefore, if n = 16, then:
\[ 2n = 2 \times 16 = 32 \]
- This means the plant cell has 32 chromosomes in total.

3. **Understand the formation of bivalents:**
- During meiosis, homologous chromosomes pair up to form bivalents. Each bivalent consists of two homologous chromosomes.

4. **Calculate the number of bivalents:**
- Since there are 32 chromosomes in total (2n = 32), and they pair up to form bivalents, the number of bivalents formed is:
\[ \text{Number of bivalents} = \frac{\text{Total chromosomes}}{2} = \frac{32}{2} = 16 \]

5. **Conclusion:**
- Therefore, in metaphase-I of meiosis, there will be 16 bivalents formed.

### Final Answer:
(c) 16 bivalents