1 molecule glucose, 6 molecules of `O_(2)` and 38 ADP combine to form `6H_(2)O,6CO_(2)`, and

Options

A. 38 molecules of ATP
B. 28 ATP
C. 38 ADP
D. 28 ADP

Answer

To solve the question, we need to analyze the process of aerobic respiration in plants, specifically how glucose is metabolized in the presence of oxygen to produce carbon dioxide, water, and ATP.

### Step-by-Step Solution:

1. **Identify the Reactants**:
- We start with 1 molecule of glucose (C6H12O6), 6 molecules of oxygen (O2), and 38 molecules of ADP (adenosine diphosphate).

2. **Identify the Products**:
- The products of aerobic respiration include 6 molecules of carbon dioxide (CO2) and 6 molecules of water (H2O).

3. **Determine the ATP Production**:
- During aerobic respiration, glucose is oxidized, and energy is released. This energy is used to convert ADP into ATP (adenosine triphosphate).
- The process of ATP production occurs through two main mechanisms: substrate-level phosphorylation and oxidative phosphorylation.

4. **Calculate the Total ATP Produced**:
- In aerobic respiration, the complete oxidation of one molecule of glucose typically yields about 38 molecules of ATP.
- Therefore, when 38 ADP molecules are used, they are converted to 38 ATP molecules.

5. **Conclusion**:
- The balanced equation for the aerobic respiration of glucose can be summarized as:
\[ C_6H_{12}O_6 + 6 O_2 + 38 ADP \rightarrow 6 CO_2 + 6 H_2O + 38 ATP \]
- Hence, the correct answer to the question is that 1 molecule of glucose, 6 molecules of O2, and 38 ADP combine to form 6 H2O, 6 CO2, and **38 ATP**.

### Final Answer:
**38 ATP**