In hexose monophosphate shunt the number of `CO_(2)` molecules evolved is

Options

A. Same as in glycolysis
B. Less than glycolysis
C. More than glycolysis
D. Much less than glycolysis

Answer

To determine the number of CO₂ molecules evolved in the hexose monophosphate shunt (also known as the pentose phosphate pathway), we can follow these steps:

### Step-by-Step Solution:

1. **Understanding the Pathway**: The hexose monophosphate shunt is also known as the pentose phosphate pathway. It occurs in the cytoplasm of the cell and is primarily responsible for the production of NADPH and ribose-5-phosphate.

2. **Starting Material**: The pathway begins with glucose-6-phosphate, which is derived from glycolysis.

3. **Production of CO₂**: During the process of the pentose phosphate pathway, one molecule of carbon dioxide (CO₂) is produced for each turn of the cycle.

4. **Comparison with Glycolysis**: In glycolysis, glucose is converted into two molecules of pyruvate, but no carbon dioxide is released during this process.

5. **Conclusion**: Since the hexose monophosphate shunt produces one molecule of CO₂ and glycolysis produces none, we can conclude that the number of CO₂ molecules evolved in the hexose monophosphate shunt is **more than glycolysis**.

### Final Answer:
The number of CO₂ molecules evolved in the hexose monophosphate shunt is **more than glycolysis**.

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