A physical parameter `a` can be determined by measuring the parameters `b, c, d, and e` using the relation `a=b^(alpha)c^(beta)//d^(gamma)e^(delta)`. If the maximum errors in the measurement of `b, c , d, and e are b_(1) %,c_(1)% ,d_(1)% , and e_(1) %`, then the maximum error in the value of `a` determined by the experminent.
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To find the maximum error in the physical parameter \( a \) determined by the relation \( a = \frac{b^{\alpha} c^{\beta}}{d^{\gamma} e^{\delta}} \), we will follow these steps:
### Step-by-Step Solution:
1. **Write the relationship**:
The relationship given is:
\[
a = \frac{b^{\alpha} c^{\beta}}{d^{\gamma} e^{\delta}}
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A physical parameter a can be determined by measuring the parameters b,c,d and e using the relation a = b^alpha c^beta //d^gamma e^delta . If the maximum errors in the measurement of b, c, d and e are b_1 % , c_1 % , d_1 % and e_1 % then the maximum error in the value of a determined by the experiment is (b_1+c_1+d_1+e_1)% (b_1+c_1-d_1-e_1)% (alphab_1+betac_1-gammad_1-deltae_1)% (alphab_1+betac_1+gammad_1+deltae_1)%
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