If there is a positive error of ` 50%` in the measurement of velocity of a body , find the error in the measurement of kinetic energy.
Text Solution
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Kinetic energy , ` E = (1)/(2) mv^(2)` :. `(Delta E)/( E) xx 100 = (( Delta m)/(m) + ( 2 Delta v )/( v)) xx 100` Here `Delta m = 0 and (Delta v) /( v) xx 100 = 50%` :. `( Delta E)/(E) xx 100 = 2 xx 50 = 100%`
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