In an experiment of simple pendulum , the time period measured was `50 s for 25` vibrations when the length of the simple pendulum was taken `100 cm`. If the least count of stop watch is `0.1 s` and that of meter scale is `0.1 cm`. Calculate the maximum possible error in the measurement of value of `g`. If the actual value of `g` at the place of experiment is `9.7720 m s^(-2) ` , Calculate the percentage error.
Text Solution
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To solve the problem, we need to follow these steps:
### Step 1: Understand the formula for the time period of a simple pendulum
The time period \( T \) of a simple pendulum is given by the formula:
\[
T = 2\pi \sqrt{\frac{L}{g}}
\]
where:
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