If the measured value of resistance `R = 1.05 Omega`, wire diameter ` d = 0.60 mm` , and length `l = 75.3 cm`, then find the maximum permissible error in resistivity , ` rho = ( R ( pi d^(2) // 4)) /( l)`.
Text Solution
AI Generated Solution
To find the maximum permissible error in resistivity, we will use the formula for resistivity given by:
\[
\rho = \frac{R \left( \frac{\pi d^2}{4} \right)}{l}
\]
Where:
- \( R \) is the resistance
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