In Searle's exp to find Young's modulus, the diameter of wire is mesured as `D=0.05cm` length of wire is `L=125cm`, and when a weight, `m=20.0 kg` is put, extension in wire was found to be `0.100cm`. Find maximum permissible percentage error in Young's modulus (`Y`)
Text Solution
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To find the maximum permissible percentage error in Young's modulus (Y), we start with the formula for Young's modulus:
\[
Y = \frac{F \cdot L}{A \cdot \Delta L}
\]
Where:
- \( F \) is the force applied (which is equal to \( mg \))
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