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You may not know integration , but using...

You may not know integration , but using dimensional analysis you can check on some results . In the integral `int ( dx)/(( 2ax - x^(2))^(1//2)) = a^(n) sin^(-1) ((x)/(a) -1)`, find the valiue of `n` .

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To find the value of \( n \) in the equation \[ \int \frac{dx}{(2ax - x^2)^{1/2}} = a^n \sin^{-1}\left(\frac{x}{a} - 1\right), \] we will use dimensional analysis. ...
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