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The position of a particle at time t is ...

The position of a particle at time `t` is given by the relation `x(t) = ( v_(0) /( alpha)) ( 1 - c^(-at))`, where `v_(0)` is a constant and `alpha gt 0`. Find the dimensions of `v_(0) and alpha`.

A

`M^(0) LT^(-1) and T^(-1)`

B

`M^(0) LT^(1) and T^(-1)`

C

`M^(0) LT^(-1) and LT^(-2)`

D

`M^(0) LT^(-1) and T`

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The correct Answer is:
To find the dimensions of \( v_0 \) and \( \alpha \) in the given position equation \( x(t) = \frac{v_0}{\alpha} (1 - c^{-at}) \), we will analyze the equation step by step. ### Step 1: Identify the dimensions of position The left-hand side of the equation represents the position \( x(t) \). The dimension of position is given by: \[ [x] = L \] where \( L \) represents length. ### Step 2: Analyze the right-hand side of the equation The right-hand side of the equation is \( \frac{v_0}{\alpha} (1 - c^{-at}) \). Since \( 1 \) is dimensionless, the term \( \frac{v_0}{\alpha} \) must also be dimensionless. Therefore: \[ \left[ \frac{v_0}{\alpha} \right] = 1 \] ### Step 3: Set up the relationship for dimensions From the above, we can express the dimensions as: \[ [v_0] = [\alpha] \] This means that the dimensions of \( v_0 \) must be equal to the dimensions of \( \alpha \) multiplied by a dimensionless quantity. ### Step 4: Analyze the term \( c^{-at} \) The term \( c^{-at} \) must also be dimensionless. Since \( a \) is a constant, we can analyze the dimensions of \( at \): \[ [at] = 1 \quad \text{(dimensionless)} \] This implies that the dimension of \( a \) must be the inverse of the dimension of time: \[ [a] = T^{-1} \] Thus, we can conclude that \( \alpha \) must also have the dimension of \( T^{-1} \). ### Step 5: Determine the dimensions of \( v_0 \) Now, since we established that: \[ [v_0] = [\alpha] \cdot [L] \] and knowing that \( [\alpha] = T^{-1} \), we can express the dimensions of \( v_0 \) as: \[ [v_0] = L \cdot T^{-1} \] ### Final Results Thus, we have: - The dimensions of \( v_0 \) are \( [v_0] = LT^{-1} \) - The dimensions of \( \alpha \) are \( [\alpha] = T^{-1} \) ### Summary of Dimensions - \( v_0 \) has dimensions of speed (length per time). - \( \alpha \) has dimensions of frequency (inverse time).

To find the dimensions of \( v_0 \) and \( \alpha \) in the given position equation \( x(t) = \frac{v_0}{\alpha} (1 - c^{-at}) \), we will analyze the equation step by step. ### Step 1: Identify the dimensions of position The left-hand side of the equation represents the position \( x(t) \). The dimension of position is given by: \[ [x] = L \] where \( L \) represents length. ...
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