Home
Class 11
PHYSICS
The resistance of a metal is given by R ...

The resistance of a metal is given by `R = V//I` , where `V` is potential difference and `I` is current . In a circuit , the potential difference across resistance is `V = ( 8 +- 0.5) V` and current in resistance , `I = ( 4 +- 0.2)A`. What is the value of resistance with its percentage error?

A

`( 2 +- 5.6%) Omega`

B

`( 2 +- 0.7%) Omega`

C

`( 2 +- 35%) Omega`

D

`( 2 +- 11.25%) Omega`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to calculate the resistance \( R \) using the formula \( R = \frac{V}{I} \), where \( V \) is the potential difference and \( I \) is the current. We also need to determine the percentage error in the resistance based on the errors in the measurements of \( V \) and \( I \). ### Step 1: Calculate the resistance \( R \) Given: - \( V = 8 \, \text{V} \) - \( I = 4 \, \text{A} \) Using the formula: \[ R = \frac{V}{I} = \frac{8 \, \text{V}}{4 \, \text{A}} = 2 \, \Omega \] ### Step 2: Determine the errors in \( V \) and \( I \) Given: - Error in \( V \) (denoted as \( \Delta V \)) = \( 0.5 \, \text{V} \) - Error in \( I \) (denoted as \( \Delta I \)) = \( 0.2 \, \text{A} \) ### Step 3: Calculate the relative error in resistance \( R \) The formula for the relative error in \( R \) is given by: \[ \frac{\Delta R}{R} = \frac{\Delta V}{V} + \frac{\Delta I}{I} \] Substituting the values: \[ \frac{\Delta R}{R} = \frac{0.5}{8} + \frac{0.2}{4} \] Calculating each term: \[ \frac{0.5}{8} = 0.0625 \] \[ \frac{0.2}{4} = 0.05 \] Adding these values together: \[ \frac{\Delta R}{R} = 0.0625 + 0.05 = 0.1125 \] ### Step 4: Calculate the absolute error in \( R \) Now, we can find the absolute error \( \Delta R \): \[ \Delta R = R \times \frac{\Delta R}{R} = 2 \times 0.1125 = 0.225 \, \Omega \] ### Step 5: Calculate the percentage error in \( R \) The percentage error is given by: \[ \text{Percentage error} = \left( \frac{\Delta R}{R} \right) \times 100 = 0.1125 \times 100 = 11.25\% \] ### Final Result Thus, the resistance with its percentage error is: \[ R = 2 \, \Omega \pm 11.25\% \]

To solve the problem, we need to calculate the resistance \( R \) using the formula \( R = \frac{V}{I} \), where \( V \) is the potential difference and \( I \) is the current. We also need to determine the percentage error in the resistance based on the errors in the measurements of \( V \) and \( I \). ### Step 1: Calculate the resistance \( R \) Given: - \( V = 8 \, \text{V} \) - \( I = 4 \, \text{A} \) ...
Promotional Banner

Topper's Solved these Questions

  • DIMENSIONS & MEASUREMENT

    CENGAGE PHYSICS ENGLISH|Exercise Multiple Correct|2 Videos
  • DIMENSIONS & MEASUREMENT

    CENGAGE PHYSICS ENGLISH|Exercise Linked Comprehension|3 Videos
  • DIMENSIONS & MEASUREMENT

    CENGAGE PHYSICS ENGLISH|Exercise Subjective|31 Videos
  • CENTRE OF MASS

    CENGAGE PHYSICS ENGLISH|Exercise INTEGER_TYPE|1 Videos
  • FLUID MECHANICS

    CENGAGE PHYSICS ENGLISH|Exercise INTEGER_TYPE|1 Videos

Similar Questions

Explore conceptually related problems

The resistance of metal is given by V = IR , The voltage in the resistance is V = (8 pm 0.5)V and current in the resistance is I = (2 +- 0.2)A , the value fo resistance with its percentage error is

For a metallic wire, the ratio V/i ( V= applied potential difference and i= current flowing ) is

Give, potential difference V = (8 + 0.5) V and current I = (2 + 0.2) A. The value of resistance R is

Potential difference across AB , i.e., V_(A)-V_(B) is

If the potential difference between A and D is V, what will be potential difference between F and C. each of the resistance is R.

In the given circuit, if the potential difference across the internal resistance r_1 is equal to E, then the resistance R is equal to:

In the circuit the potential difference across the capacitor is 10 V . Each resistance is of 3Omega The cell is ideal. The emf of the cell is

How are the potential difference (V), current (I) and resistance (R) related ?

In Ohm's law experiment , the potential drop acros a resistance was as V = 5.0 V and the current was measured as I = 2.00 A . Find the maximum permissible error in resistance.

In the L-R circuit as shown in figure, potential difference across the resistance at some instant is 4 V. Then

CENGAGE PHYSICS ENGLISH-DIMENSIONS & MEASUREMENT-Single Correct
  1. Percentage erros in the measurement of mass and speed are 2% and 3% re...

    Text Solution

    |

  2. An experiment from X = (a^(1//2) b^(2))/( c^(3)) . If the percentage e...

    Text Solution

    |

  3. The resistance of a metal is given by R = V//I , where V is potential ...

    Text Solution

    |

  4. Which of the following product of e , h , mu , G ( where mu is permea...

    Text Solution

    |

  5. Which of the following does not have the dimensions of velocity ? ( Gi...

    Text Solution

    |

  6. The mass of the liquid flowing per second per unit area of cross-secti...

    Text Solution

    |

  7. A physical quantity x is calculated from x = ab^(2)//sqrt(c ). Calcul...

    Text Solution

    |

  8. Given that Y = a sin omegat + bt + ct^(2) cos omegat. The unit of abc ...

    Text Solution

    |

  9. The potential energy of a particle varies with distance x from a fixed...

    Text Solution

    |

  10. If x and a stand for distance , then for what value of n is the given ...

    Text Solution

    |

  11. The specific resistance rho of a circular wire of radius r, resistance...

    Text Solution

    |

  12. Using mass (M) , length (L) , time (T) , and electric current (A) as f...

    Text Solution

    |

  13. Assuming that the mass m of the largest stone that can be moved by a f...

    Text Solution

    |

  14. A sperical body of mass m and radius r is allowed to fall in a medium ...

    Text Solution

    |

  15. A student writes four different expressions for the displacement y in ...

    Text Solution

    |

  16. The relation tan theta = v^(2)// r g gives the angle of banking of th...

    Text Solution

    |

  17. A liquid drop of density rho , radius r, and surface tension sigma osc...

    Text Solution

    |

  18. A highly rigid cubical block A of small mass M and side L is fixed rig...

    Text Solution

    |

  19. The mass of a body is 20.000 g and its volume is 10.00 cm^(3). If the ...

    Text Solution

    |

  20. The length of a strip measured with a meter rod is 10.0cm. Its width m...

    Text Solution

    |