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Which of the following pairs have the sa...

Which of the following pairs have the same dimensions?

A

` h//e` and magnetic flux

B

` h//e` and electric flux

C

Electric fux and `q//epsilon_(0)`

D

Electric flux and `mu_(0)I`

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To determine which pairs have the same dimensions, we will analyze the dimensions of the given quantities step by step. ### Step 1: Analyzing H/E 1. **Identify H**: The quantity H (magnetic field strength) has units of Joule per second (J/s). - Joule (J) = kg·m²/s², so: - H = J/s = (kg·m²/s²) / s = kg·m²/s³ = [M L² T⁻³] 2. **Identify E**: The quantity E (electric field) has units of voltage (V) per unit of charge (C). - Voltage (V) = J/C = (kg·m²/s²) / (A·s) = kg·m²/(A·s³), so: - E = V/C = (kg·m²/(A·s³)) / (A·s) = kg·m²/(A²·s⁴) = [M L² T⁻⁴ A⁻²] 3. **Calculate H/E**: - H/E = [M L² T⁻³] / [M L² T⁻⁴ A⁻²] = [A² T] = [M L² T⁻² A⁻¹] ### Step 2: Analyzing Magnetic Flux 1. **Magnetic Flux (Φ)**: Magnetic flux is defined as the product of the magnetic field (B) and the area (A). - The dimension of magnetic flux (Φ) is given by: - Φ = B·A - We know B = F/(I·L), where F = M L T⁻², I = A, and L = L. - Thus, B = [M L T⁻²] / [A·L] = [M T⁻² A⁻¹]. 2. **Area (A)**: The dimension of area is L². 3. **Combine dimensions**: - Φ = [M T⁻² A⁻¹]·[L²] = [M L² T⁻² A⁻¹]. ### Step 3: Compare H/E and Magnetic Flux - From the calculations: - H/E = [M L² T⁻² A⁻¹] - Magnetic Flux = [M L² T⁻² A⁻¹] Thus, H/E and Magnetic Flux have the same dimensions. ### Step 4: Analyzing Electric Flux 1. **Electric Flux (Φ_e)**: Electric flux is defined as the charge (Q) divided by the permittivity (ε₀). - Φ_e = Q / ε₀. 2. **Charge (Q)**: The dimension of charge is given by: - Q = [A·T]. 3. **Permittivity (ε₀)**: The dimension of permittivity is: - ε₀ = [M⁻¹ L⁻³ T⁴ A²]. 4. **Combine dimensions**: - Φ_e = [A·T] / [M⁻¹ L⁻³ T⁴ A²] = [M L³ T⁻³ A⁻¹]. ### Step 5: Final Comparison - Electric Flux = [M L³ T⁻³ A⁻¹]. - This is different from the dimensions of H/E and Magnetic Flux. ### Conclusion The pairs that have the same dimensions are: 1. H/E and Magnetic Flux.

To determine which pairs have the same dimensions, we will analyze the dimensions of the given quantities step by step. ### Step 1: Analyzing H/E 1. **Identify H**: The quantity H (magnetic field strength) has units of Joule per second (J/s). - Joule (J) = kg·m²/s², so: - H = J/s = (kg·m²/s²) / s = kg·m²/s³ = [M L² T⁻³] 2. **Identify E**: The quantity E (electric field) has units of voltage (V) per unit of charge (C). ...
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