Home
Class 11
PHYSICS
If S and V are one main scale and one Ve...

If `S and V` are one main scale and one Vernier scale and ` n - 1` divisions on the main scale are equivalent to `n` divisions of the Vernier , then

A

The least count is `S//n`.

B

The Vernier constant is `S//n`.

C

The same Vernier constant can be used for circular Vernier also.

D

The same vernier constant cannot be used for circular Verniers.

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to understand the relationship between the main scale (S) and the Vernier scale (V) in terms of their divisions. The question states that \( n - 1 \) divisions on the main scale are equivalent to \( n \) divisions on the Vernier scale. ### Step-by-Step Solution: 1. **Understanding the Given Information:** - We have \( n - 1 \) divisions of the main scale (MSD) equal to \( n \) divisions of the Vernier scale (VSD). - This can be expressed mathematically as: \[ (n - 1) \times \text{MSD} = n \times \text{VSD} \] 2. **Finding the Value of One Vernier Scale Division (VSD):** - Rearranging the above equation gives: \[ \text{VSD} = \frac{(n - 1)}{n} \times \text{MSD} \] 3. **Calculating the Least Count (LC):** - The least count of the Vernier scale is defined as: \[ \text{Least Count} = \text{MSD} - \text{VSD} \] - Substituting the value of VSD from the previous step: \[ \text{Least Count} = \text{MSD} - \frac{(n - 1)}{n} \times \text{MSD} \] - Simplifying this expression: \[ \text{Least Count} = \text{MSD} \left(1 - \frac{(n - 1)}{n}\right) = \text{MSD} \left(\frac{1}{n}\right) \] 4. **Conclusion:** - Therefore, we find that the least count of the Vernier scale is: \[ \text{Least Count} = \frac{\text{MSD}}{n} \] - Since the problem states that \( S \) is the main scale and \( V \) is the Vernier scale, we can conclude: \[ \text{Least Count} = \frac{S}{n} \] 5. **Vernier Constant:** - The Vernier constant is also equal to the least count, which we have derived as \( \frac{S}{n} \). ### Final Answer: - The least count of the Vernier scale is \( \frac{S}{n} \). - The Vernier constant is also \( \frac{S}{n} \). - This can be used for circular Verniers as well.

To solve the problem, we need to understand the relationship between the main scale (S) and the Vernier scale (V) in terms of their divisions. The question states that \( n - 1 \) divisions on the main scale are equivalent to \( n \) divisions on the Vernier scale. ### Step-by-Step Solution: 1. **Understanding the Given Information:** - We have \( n - 1 \) divisions of the main scale (MSD) equal to \( n \) divisions of the Vernier scale (VSD). - This can be expressed mathematically as: \[ ...
Promotional Banner

Topper's Solved these Questions

  • DIMENSIONS & MEASUREMENT

    CENGAGE PHYSICS ENGLISH|Exercise Multiple Correct|2 Videos
  • DIMENSIONS & MEASUREMENT

    CENGAGE PHYSICS ENGLISH|Exercise Linked Comprehension|3 Videos
  • DIMENSIONS & MEASUREMENT

    CENGAGE PHYSICS ENGLISH|Exercise Subjective|31 Videos
  • CENTRE OF MASS

    CENGAGE PHYSICS ENGLISH|Exercise INTEGER_TYPE|1 Videos
  • FLUID MECHANICS

    CENGAGE PHYSICS ENGLISH|Exercise INTEGER_TYPE|1 Videos

Similar Questions

Explore conceptually related problems

The main scale of a vernier callipers is calibrated in mm and 19 divisions of main scale are equal in length to 20 divisions of vernier scale. In measuring the diameter of a cylinder by this instrument, the main scale reads 35 divisions and the 4th division of vernier scale coincides with a main scale division. Find least count .

The main scale of a vernier callipers is calibrated in mm and 19 divisions of main scale are equal in length to 20 divisions of vernier scale. In measuring the diameter of a cylinder by this instrument, the main scale reads 35 divisions and the 4th division of vernier scale coincides with a main scale division. Find radius of cylinder.

The length of an object is measured using a vernier system whose main scale is 30 cm long with 600 divisions. If 19 divisions of the main scale coincide with 20 divisions of the vernier scale, then its least count is

The edge of a cube is measured using a vernier callipers. [ 9 divisions of the main scale is equal to 10 divisions of the vernier scale and 1 main scale dividsion is 1 mm ]. The main scale division reading is 10 and 1st division of vernier scale was found to be coinciding with the main scale. The mass of the cube is 2.736 g . Calculate the density in g//cm^3 upto correct significant figures.

The least count of a veriner callipers is (1)/(100)cm . The value of one division on the main scale is 1mm. The, the number of divisions on the main scale that coincide with N divisions of the vernier is

N divisions on the main scale of a vernier callipers coincide with (N + 1) divisions on the vernier scale. If each division on the main scale is 'a' units, then the least count of the instrument is

In a vernier callipers, one main scale division is x cm and n divisions of the vernier scale coincide with (n-1) divisions of the main scale. The least count (in cm) of the callipers is :-

The diameter of a cylinder is measured using a Vernier callipers with no zero error. It is found that the zero of the Vernier scale lies between 5.10cm and 5.15cm of the main scale. The Vernier scale has 50 divisions equivalent to 2.45 cm . The 24^(th) division of the Vernier scale exactly coincides with one of the main scale divisions. the diameter of the cylinder is

In a vernier calipers, 1 cm of the main scale is divided into 20 equal parts. 19 divisions of the main scale coincide with 20 divisions on the vernier scale . Find the least count of the instrument.

Read the vermier 10 division of vermier scale are matching with 9 divisionsd of main scale

CENGAGE PHYSICS ENGLISH-DIMENSIONS & MEASUREMENT-Single Correct
  1. While measuring acceleration due to gravity by a simple pendulum , a s...

    Text Solution

    |

  2. The relative density of a material is found by weighing the body first...

    Text Solution

    |

  3. The dimensional formula for a physical quantity x is [M^(-1) L^(3) T^(...

    Text Solution

    |

  4. The heat generated in a circuit is given by Q = I^(2) Rt , where I is ...

    Text Solution

    |

  5. The internal and external diameters of a hollow cylinder are measured ...

    Text Solution

    |

  6. Which of the following pairs has the same dimensions?

    Text Solution

    |

  7. Which of the following pairs have different dimensions?

    Text Solution

    |

  8. Pressure is dimensionally

    Text Solution

    |

  9. Which of the following pairs have the same dimensions ? (L = induct...

    Text Solution

    |

  10. Choose the correct statement(s).

    Text Solution

    |

  11. Which of the following pairs have the same dimensions?

    Text Solution

    |

  12. The values of measurement of a physical quantity in five trails were f...

    Text Solution

    |

  13. If S and V are one main scale and one Vernier scale and n - 1 divisio...

    Text Solution

    |

  14. Consider three quantities: x = (E)/( b) , y = (1)/(sqrt( mu(0) epsilon...

    Text Solution

    |

  15. The van der Waal's equation of state for some gases can be expressed a...

    Text Solution

    |

  16. The van der Waal's equation of state for some gases can be expressed a...

    Text Solution

    |

  17. The van der Waal's equation of state for some gases can be expressed a...

    Text Solution

    |

  18. The van der Waal's equation of state for some gases can be expressed a...

    Text Solution

    |

  19. The van der Waal's equation of state for some gases can be expressed a...

    Text Solution

    |

  20. Dimensionsal methods provide three major advantages in verification , ...

    Text Solution

    |