The accuracy of measurement also lies in the way the results is expressed. The number of digits to which a value is to be expressed is one digit more than number of digits after after an operation is carried out on the given values. The error can be minimised by many trials and using the correct methods are instruments.
The order of magnitude of `147` is

Options

A. `1`
B. `2`
C. `3`
D. `4`

Explanation

To find the order of magnitude of the number 147, we can follow these steps:

### Step-by-Step Solution:

1. **Understanding Order of Magnitude**:
The order of magnitude of a number is defined as the power of 10 when the number is expressed in the form \( a \times 10^n \), where \( a \) is a number between 0.5 and 5, and \( n \) is an integer.

2. **Expressing 147 in Scientific Notation**:
We need to express 147 in the form \( a \times 10^n \). To do this, we can identify where the decimal point would be in the number 147. The number can be written as:
\[ 147 = 1.47 \times 10^2 \]

3. **Shifting the Decimal Point**:
- Initially, the decimal point in 147 is at the end of the number (147.0).
- To convert 147 into the form \( a \times 10^n \), we shift the decimal point two places to the left to get 1.47.
- Since we shifted the decimal point two places to the left, we multiply by \( 10^2 \) to maintain the equality.

4. **Checking the Value of \( a \)**:
- Now, we check if \( a = 1.47 \) meets the criteria for the order of magnitude:
- Is \( 1.47 \geq 0.5 \)? Yes.
- Is \( 1.47 < 5 \)? Yes.
- Therefore, \( 1.47 \) is a valid representation.

5. **Determining the Order of Magnitude**:
- The exponent \( n \) in our expression \( 1.47 \times 10^2 \) is 2.
- Thus, the order of magnitude of 147 is 2.

### Final Answer:
The order of magnitude of 147 is **2**.

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