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The number of circular divisions of shown screw gauge are 50. It moves 0.5 mm on main scale in one rotation. The diameter of the ball is:

A

a. `1.2 mm`

B

b. `1.25 mm`

C

c. `2.20 mm`

D

d. `2.25 mm`

Text Solution

Verified by Experts

The correct Answer is:
A
`"Least count" = ("Pitch")/("Number of division on circular scale") = ( 0.5)/( 50)`
`= 0.01 mm`
Now , diameter of ball `= (2 xx 0.5 ) + ( 25 - 5) (0.01) = 1.2 mm `
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