Home
Class 11
PHYSICS
A student uses a simple pendulum of exac...

A student uses a simple pendulum of exactly 1 m length to determine g, the acceleration due to gravity. He uses a stopwatch with the least count of 1 second for this and records 40 seconds for 20 oscillations. For this observation, which of the following statements is true?

A

Error `Delta T` in measuring `T` , the time period , is `0.05 s`

B

Error `Delta T` in measuring `T` , the time period , is `1 s`

C

Percentage error in the determination of `g is 5%`

D

Percentage error in the determination of `g is 2.5%`

Text Solution

Verified by Experts

The correct Answer is:
A, C
`T = 40// 20 = 2 s`
`(Delta T)/( T) = ( Delta t)/( t) = (1)/( 40) rArr Delta T = (T)/( 40) = (2)/( 40) = 0.05 s`
` g = ( 4 pi^(2) L n^(2))/( t^(2)) where t = nT`
`( Delta g)/(g) = ( 2 Delta t)/(t) rArr %error = ( 2Delta t)/( t) xx 100 = 5%`
Promotional Banner

Topper's Solved these Questions

  • DIMENSIONS & MEASUREMENT

    CENGAGE PHYSICS ENGLISH|Exercise Integer|2 Videos

  • DIMENSIONS & MEASUREMENT

    CENGAGE PHYSICS ENGLISH|Exercise Single correct Answer Type|15 Videos

  • CENTRE OF MASS

    CENGAGE PHYSICS ENGLISH|Exercise INTEGER_TYPE|1 Videos

  • FLUID MECHANICS

    CENGAGE PHYSICS ENGLISH|Exercise INTEGER_TYPE|1 Videos

Similar Questions

Explore conceptually related problems

A student uses a simple pendulum of exactly 1m length to determine g , the acceleration due ti gravity. He uses a stop watch with the least count of 1sec for this and record 40 seconds for 20 oscillations for this observation, which of the following statement (s) is (are) true?

Student I ,II , and III perform an experiment for measuring the acceleration due to gravity (g) usinf a simple pendulum. They use lengths of the pendulum and // or record time for different number of oscillations . The observations are shown in the following table . Least count for length = 0.1 cm {:(underset(III)underset(II)underset(I)underset()underset()("Student"),underset(20.0)underset(64.0)underset(64.0)underset((cm))underset("Pendulam")("Length of "),underset(4)underset(4)underset(8)underset((n))underset("n Oscillation")("Number of"),underset(9.0)underset(16.0)underset(16.0)underset((s))underset("Period")("Time")):} Least count for time = 0.1 s . If E_(I), E_(II) , and E_(III) are the percentage errors in g , i.,e., ((Delta g)/( g) xx 100) for students I,II , and III, respectively , then

In an experiment to determine the acceleration due to gravity at a place a stop watch with a resolution of 0.2 s was used and total time for a certain number of oscillations was measured as 100.2s. Claculate the maximum error in the time period? If the percentage error in measuring the length of he pendulum is 0.3%, what is the percentage error in the value of g?

Students J_(1) , J_(2) , J_(3) and J_(4) perform an experiment for measuring the acceleration due to gravity (g) using a simple pendulum, they use different lengths of the pendulum and record time for different number of oscillations. The observations are shown in the table. Least count for length = 0.1 cm , least count for time = 1s {:("Students",underset("pendulum (cm)")("Length of the"),underset("oscillations(n)")("No.of"),underset("of pendulum (s)")("Time period")),(I_(1),100.0,20,20),(J_(1),400.0,10,40),(J_(1),100.0,10,20),(I_(1),400.0,20,40):} If P_(1),P_(2),P_(3) and P_(4) are the % error in g for students J_(1) , J_(2) , J_(3) and J_(4) respectively then -

The time period of a simple pendulum is given by T = 2 pi sqrt(L//g) , where L is length and g acceleration due to gravity. Measured value of length is 10 cm known to 1 mm accuracy and time for 50 oscillations of the pendulum is 80 s using a wrist watch of 1 s resloution. What is the accuracy in the determination of g ?

A simple pendulum of length 'L' has mass 'M' and it oscillates freely with amplitude A, Energy is (g = acceleration due to gravity)

A simple pendulum is being used to determine the value of gravitational acceleration g at a certain place. The length of the pendulum is 25.0 cm and a stop watch with 1 s resolution measures the time taken for 40 oscillations to be 50 s. The accuracy in g is:

In an experiment of determine acceleration due to gravity by simple pendulum, a student commits 1% positive error in the measurement of length and 3% negative error in the time then % error in g will be

Time is measured using a stop watch of least count 0.1 second In 10 oscilation time taken is 20.0 second Find maximum permissible error in time period .

A simple pendulum of length 1 feet suspended from the ceiling of an elevator takes pi/3 seconds to complete one oscilation. Find the acceleration of the elevator.