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A vector perpendicular to hat(i)+hat(j)+...

A vector perpendicular to `hat(i)+hat(j)+hat(k)` is

A

`hat(i)-hat(j)+hat(k)`

B

`hat(i)-hat(j)-hat(k)`

C

`-hat(i)-hat(j)-hat(k)`

D

`3hat(i)+2hat(j)-5hat(k)`

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AI Generated Solution

The correct Answer is:
To find a vector that is perpendicular to the vector \( \hat{i} + \hat{j} + \hat{k} \), we can use the property of the dot product. Two vectors \( \mathbf{A} \) and \( \mathbf{B} \) are perpendicular if their dot product is zero, i.e., \( \mathbf{A} \cdot \mathbf{B} = 0 \). ### Step-by-Step Solution: 1. **Identify the Given Vector:** The vector we are given is: \[ \mathbf{A} = \hat{i} + \hat{j} + \hat{k} \] 2. **Choose Options for Vector \( \mathbf{B} \):** We will check each of the given options to see if they are perpendicular to \( \mathbf{A} \). 3. **Check Option 1: \( \mathbf{B} = \hat{i} - \hat{j} + \hat{k} \)** - Calculate the dot product: \[ \mathbf{A} \cdot \mathbf{B} = (\hat{i} + \hat{j} + \hat{k}) \cdot (\hat{i} - \hat{j} + \hat{k}) = 1 - 1 + 1 = 1 \] - Since \( \mathbf{A} \cdot \mathbf{B} \neq 0 \), this option is incorrect. 4. **Check Option 2: \( \mathbf{B} = \hat{i} - \hat{j} - \hat{k} \)** - Calculate the dot product: \[ \mathbf{A} \cdot \mathbf{B} = (\hat{i} + \hat{j} + \hat{k}) \cdot (\hat{i} - \hat{j} - \hat{k}) = 1 - 1 - 1 = -1 \] - Since \( \mathbf{A} \cdot \mathbf{B} \neq 0 \), this option is also incorrect. 5. **Check Option 3: \( \mathbf{B} = -\hat{i} - \hat{j} - \hat{k} \)** - Calculate the dot product: \[ \mathbf{A} \cdot \mathbf{B} = (\hat{i} + \hat{j} + \hat{k}) \cdot (-\hat{i} - \hat{j} - \hat{k}) = -1 - 1 - 1 = -3 \] - Since \( \mathbf{A} \cdot \mathbf{B} \neq 0 \), this option is incorrect. 6. **Check Option 4: \( \mathbf{B} = 3\hat{i} + 2\hat{j} - 5\hat{k} \)** - Calculate the dot product: \[ \mathbf{A} \cdot \mathbf{B} = (\hat{i} + \hat{j} + \hat{k}) \cdot (3\hat{i} + 2\hat{j} - 5\hat{k}) = 3 + 2 - 5 = 0 \] - Since \( \mathbf{A} \cdot \mathbf{B} = 0 \), this option is correct. ### Conclusion: The vector that is perpendicular to \( \hat{i} + \hat{j} + \hat{k} \) is: \[ \mathbf{B} = 3\hat{i} + 2\hat{j} - 5\hat{k} \]

To find a vector that is perpendicular to the vector \( \hat{i} + \hat{j} + \hat{k} \), we can use the property of the dot product. Two vectors \( \mathbf{A} \) and \( \mathbf{B} \) are perpendicular if their dot product is zero, i.e., \( \mathbf{A} \cdot \mathbf{B} = 0 \). ### Step-by-Step Solution: 1. **Identify the Given Vector:** The vector we are given is: \[ \mathbf{A} = \hat{i} + \hat{j} + \hat{k} ...
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CENGAGE PHYSICS ENGLISH-VECTORS-Exercise Single Correct
  1. The sum and diffrence of two perpendicular vector of equal length are

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  2. The minimum number of vector having different planes which can be adde...

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  3. A vector perpendicular to hat(i)+hat(j)+hat(k) is

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  4. From figure the correct relation is

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  5. Out of the following set of forces, the rsultant of which cannot be ze...

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  6. The resultant of two vectors vec(A) and vec(B) is perpendicular to the...

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  7. The ratio of maximum and minimum magnitudes of the resultant of two ve...

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  8. Two forces, each equal to F, act as shown in (figure) Their resultant ...

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  9. Vector vec(A) is 2cm long and is 60^(@) above the x-axis in the first ...

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  10. What is the angle between two vector forces of equal magnitude such th...

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  11. The angle between vec(A)+vec(B) and vec(A)xxvec(B) is

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  12. The projection of a vector vec(r )=3hat(i)+hat(j)+2hat(k) on the x-y p...

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  13. If |vec(A)+vec(B)|=|vec(A)|=|vec(B)| then the angle between vec(A) and...

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  14. If vectors A=hati+2hatj+4hatk and B=5hati represent the two sides of a...

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  15. Given |vec(A)(1)|=2,|vec(A)(2)|=3 and |vec(A)(1)+vec(A)(2)|=3. Find th...

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  16. Three vector vec(A),vec(B), vec(C ) satisfy the relation vec(A)*vec(B)...

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  17. If vec(A)=vec(B)+vec(C ), and the magnitudes of vec(A),vec(B),vec(C ) ...

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  18. Let A=hatiA cos theta+hatj A sin theta be any vector .Another vector B...

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  19. The angle which the vector vec(A)=2hat(i)+3hat(j) makes with the y-axi...

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  20. Given vec(P)=3hat(i)-4hat(j). Which of the following is perpendicular ...

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