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The resultant of two vectors vec(A) and ...

The resultant of two vectors `vec(A)` and `vec(B)` is perpendicular to the vector `vec(A)` and its magnitudes is equal to half of the magnitudes of vector `vec(B)` (figure). The angle between `vec(A)` and `vec(B)` is

A

a. `120^(@)`

B

b. `150^(@)`

C

c. `135^(@)`

D

d. None of these

Text Solution

Verified by Experts

The correct Answer is:
B
`cos beta=R/B=1/2rArr beta= 60^(@)`
Angle between `vec(A)` and `vec(B)= 90^(@)+beta=150^(@)`
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