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If the angle between the vectors vec(a) ...

If the angle between the vectors `vec(a)` and `vec(b)` is an acute angle, then the diffrence `vec(a)-vec(b)` is

A

The major diagonal of the parallelogram

B

The minor diagnol of the parallelogram

C

Any of the above

D

None of the above

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The correct Answer is:
To solve the problem, we need to analyze the vectors \(\vec{a}\) and \(\vec{b}\) and their relationship when the angle between them is acute. Here’s a step-by-step solution: ### Step 1: Understand the Vectors We have two vectors, \(\vec{a}\) and \(\vec{b}\), with an acute angle \(\theta\) between them. An acute angle means \(0 < \theta < 90^\circ\). **Hint:** Remember that an acute angle is less than 90 degrees. ### Step 2: Visualize the Vectors Draw the vectors \(\vec{a}\) and \(\vec{b}\) originating from the same point. Since the angle is acute, \(\vec{b}\) will be positioned such that it is within the first quadrant relative to \(\vec{a}\). **Hint:** Sketch the vectors on a coordinate plane to visualize their positions. ### Step 3: Construct the Parallelogram To find \(\vec{a} - \vec{b}\), we can use the parallelogram law. Draw \(\vec{b}\) in the opposite direction to get \(-\vec{b}\). Now, you can form a parallelogram with \(\vec{a}\) and \(-\vec{b}\). **Hint:** The diagonal of the parallelogram formed by \(\vec{a}\) and \(-\vec{b}\) represents the vector \(\vec{a} - \vec{b}\). ### Step 4: Analyze the Resulting Vector The diagonal that represents \(\vec{a} - \vec{b}\) will be the minor diagonal of the parallelogram. Since \(\vec{a}\) is longer than \(\vec{b}\) (as the angle is acute), \(\vec{a} - \vec{b}\) will also point in the same general direction as \(\vec{a}\). **Hint:** The direction of \(\vec{a} - \vec{b}\) will be similar to that of \(\vec{a}\) because \(\vec{a}\) is greater than \(\vec{b}\). ### Step 5: Conclusion Since \(\vec{a}\) is greater than \(\vec{b}\) and the angle between them is acute, the resultant vector \(\vec{a} - \vec{b}\) will also be a vector pointing in the same direction as \(\vec{a}\) but with a smaller magnitude than \(\vec{a}\). **Final Answer:** The difference \(\vec{a} - \vec{b}\) is a vector that points in the same direction as \(\vec{a}\) and has a magnitude less than that of \(\vec{a}\).

To solve the problem, we need to analyze the vectors \(\vec{a}\) and \(\vec{b}\) and their relationship when the angle between them is acute. Here’s a step-by-step solution: ### Step 1: Understand the Vectors We have two vectors, \(\vec{a}\) and \(\vec{b}\), with an acute angle \(\theta\) between them. An acute angle means \(0 < \theta < 90^\circ\). **Hint:** Remember that an acute angle is less than 90 degrees. ### Step 2: Visualize the Vectors ...
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CENGAGE PHYSICS ENGLISH-VECTORS-Exercise Single Correct
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  2. If vec(A) is perpendicular to vec(B), then

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  3. If the angle between the vectors vec(a) and vec(b) is an acute angle, ...

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  4. Given that vec(A)+vec(B)=vec(C ). If |vec(A)|=4, |vec(B)|=5 and |vec(C...

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  5. If vec(b)=3hat(i)+4hat(j) and vec(a)=hat(i)-hat(j) the vector having t...

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  6. Choose the wrong statement.

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  7. What displacement at an angle 60^(@) to the x-axis has an x-component ...

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  8. Mark the correct statement.

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  9. Out of the following forces, the resultant of which cannot be 10N?

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  10. Which of the following pairs of forces cannot be added to give a resul...

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  11. In an equilateral triangle ABC, AL, BM, and CN are medians. Forces alo...

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  12. The sum of two vectors A and B is at right angles to their difference....

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  13. If a parallelogram is formed with two sides represented by vector vec(...

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  14. Given that vec(A)+vec(B)=vec(C ) and that vec(C ) is perpendicular to ...

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  15. Two forces vec(F)(1)=500N due east and vec(F)(2)=250N due north have t...

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  16. Find the resultant of the three vectors vec(OA), vec(OB) and vec(OC) s...

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  17. Two vectors vec(a) and vec(b) are at an angle of 60^(@) with each othe...

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  18. The resultant of two vectors vec(P) and vec(Q) is vec(R). If vec(Q) is...

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  19. A vector vec(A) When added to the vector vec(B)=3hat(i)+4hat(j) yields...

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