Home
Class 11
PHYSICS
A body of mass m=1kg falls from a height...

A body of mass m=1kg falls from a height h=20m from the ground level .
(a) What is the magnitude of total change in momentum of the body before it strikes the ground?
(b) What is the corresponding average force experienced by it ?`(g=10ms^(-1))`

Text Solution

AI Generated Solution

To solve the problem step by step, we will break it down into two parts: (a) calculating the total change in momentum of the body before it strikes the ground, and (b) determining the average force experienced by the body. ### Part (a): Change in Momentum 1. **Identify the initial conditions**: - Mass of the body, \( m = 1 \, \text{kg} \) - Height from which it falls, \( h = 20 \, \text{m} \) - Initial velocity, \( u = 0 \, \text{m/s} \) (since it starts from rest) ...
Promotional Banner

Topper's Solved these Questions

  • NEWTON'S LAWS OF MOTION 1

    CENGAGE PHYSICS ENGLISH|Exercise Solved Examples|11 Videos
  • NEWTON'S LAWS OF MOTION 1

    CENGAGE PHYSICS ENGLISH|Exercise Exercise 6.1|11 Videos
  • MISCELLANEOUS VOLUME 2

    CENGAGE PHYSICS ENGLISH|Exercise INTEGER_TYPE|10 Videos
  • NEWTON'S LAWS OF MOTION 2

    CENGAGE PHYSICS ENGLISH|Exercise Integer type|1 Videos

Similar Questions

Explore conceptually related problems

A body of mass m=2kg falls from a height h=10m from the ground level . What is the magnitude of total change in momentum of the body before it strikes the ground?

A body of mass m falls from a height h_1 and rises to a height h_2 . The magnitude of the change in momentum during the impact with the ground.

A mass m with velocity u strikes a wall normally and returns with same speed. What is the magnitude of the change in momentum of the body when it returns.

A body of mass m = 2kg changes its velocity v_(1)=(1+2j+3k)m//s " to " v_(2)=(-2i+2j-k)m//s . during 2 seconds. (a) Find the magnitude of change in momentum of the body. (b) What is the magnitude of the average force experienced by the body?

A ball of mass 1 kg is dropped from 20 m height on ground and it rebounds to height 5m. Find magnitude of change in momentum during its collision with the ground. (Take g=10m//s^(2) )

A body of mass 0.5 kg is projected under the gravity with a speed of 98 m//s at an angle of 30^(@) with the horizontal. The change in momentum (in magnitude) of the body when it strikes the ground is

A body of mass m falls from height h, on the ground, If e is the coefficient of restitution between body and the ground, then the height upto which it rises after ten collisions is

A body of mass 10 kg is kept at a height of 5 m. It is allowed to fall and reach the ground. What is the kinetic energy possessed by the body just before hitting the ground? (Take g = 10m//s^(2) ).

A body of mass 0.2 kg falls from a height of 10 m to a height of 6 m above the ground. Find the loss in potential energy taking place in the body. [g=10ms^(-2)]