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An iron ball of mass m=50 g falls from a...

An iron ball of mass m=50 g falls from a height of `(h_1)=5m` and rises upto `h_(2)=3.2m` after colliding with the horizontal surface. If the time of contant of the glass half is `Delta t=0.02s`, find the average contact force exerted on the ball by the horizontal surface.

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To find the average contact force exerted on the iron ball by the horizontal surface after it collides and rebounds, we can follow these steps: ### Step 1: Calculate the initial velocity (u) just before impact The ball falls from a height \( h_1 = 5 \, \text{m} \). We can use the third equation of motion to find the velocity just before impact. \[ u^2 = 2gh_1 \] ...
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