The ring `M_(1)` and block `M_(2)` are held in the position shown in fig. Now the system is released. If `M_(1) gt M_(2)`, find `V_(1)//V_(2)` wheb the ring `m_(1)` slides down along the smooth fixed vertical rod by the distance h.

Explanation

To solve the problem of finding the ratio \( \frac{V_1}{V_2} \) when the ring \( M_1 \) slides down a smooth vertical rod by a distance \( h \), we can follow these steps:

### Step-by-Step Solution:

1. **Understanding the System**:
- We have two masses: \( M_1 \) (the ring) and \( M_2 \) (the block).
- It is given that \( M_1 > M_2 \).
- When the system is released, \( M_1 \) will slide down the rod while \( M_2 \) will move downward.
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