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A system consists of two cubes of masses...

A system consists of two cubes of masses `m_(1)` and `m_(2)` respectively connected by a spring of force constant k. The force (F) that should be applied to the upper cube to keep it at rest for which the lower one just lifts after the force is removed is

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The situation is shown in fig. Let the applied force F compresses the spring by x, so `F_(s)=kx`. After removal of force, the spring recovers its compressed length and further extends by x. At this instant the force exerted by spring is along upward direction. Thus, to lift off the lower disk, normal reaction N becomes zero.
When force is applied and spring is compressed,
`F=F_(S)+m_(1)g` ...(i)
When `m_(2)` leaves contact (we have, N=0) with ground and spring is stretched,
`F_(S)=m_(2)g` ..(ii)
From Eqs (i) and (ii) we have `F_(min)=(m_(1)+m_(2))g`
So to lift off the lower disk, `Fge(m_(1)+m_(2))g`.
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