Water falls without splashing at a rate of `0.250 Ls^(-1)` from a height of 2.60 m into a 0.750kg bucket on a scale. If the bucket is originally empty, what does the scale read 3s after water starts to accumulate in it?

Explanation

To solve the problem, we need to determine the reading on the scale after 3 seconds of water falling into the bucket. Here’s a step-by-step solution:

### Step 1: Calculate the volume of water falling in 3 seconds
The rate of water falling is given as \(0.250 \, \text{L/s}\). To convert this to cubic meters:
\[ 0.250 \, \text{L/s} = 0.250 \times 10^{-3} \, \text{m}^3/\text{s} = 0.00025 \, \text{m}^3/\text{s} \]

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