Wind with a velocity `100km h^(-1)` blows normally against one of the walls of a house with an area of `108 m^(2)`. Calculate the force exerted on the wall if the air moves parallel to the wall after striking it and has a density of `1.2 kg m^(-3)`.

Explanation

To solve the problem, we need to calculate the force exerted on the wall by the wind. Here’s a step-by-step breakdown of the solution:

### Step 1: Convert Wind Velocity to m/s
The wind velocity is given as \(100 \, \text{km/h}\). We need to convert this to meters per second (m/s).

\[ V = 100 \, \text{km/h} = 100 \times \frac{1000 \, \text{m}}{1 \, \text{km}} \times \frac{1 \, \text{h}}{3600 \, \text{s}} = \frac{100000 \, \text{m}}{3600 \, \text{s}} \approx 27.78 \, \text{m/s} \]
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