A block of mass 1kg is kept on the tilted floor of a lift moving down with acceleration `3ms^(-2)`. If the block is released from rest as shown, what will be the time taken by block to reach the bottom? What is the normal reaction on the block during the motion?

Explanation

Normal to inclined the object is at rest
`N=mg cos 37^(@)-ma cos 37^(@)`
`=m(g-a)* cos 37^(@)`
`=1 xx 7 xx 4/5 =28/5 N`
`mg sin 37^(@)-ma sin 37^(@)=ma_(rel)`
`a_(rel)=(g-a) sin 37^(@)`
`=(10-3) xx 3/5 =21/5 ms^(-2)`
`s_(rel)=u_(rel)t+1/2 a_(rel)t^(2) implies 2.1=0+1/2 ((21)/(5))t^(2)implies t=1`.