A particle of mass m moving with velocity u makes an elastic one dimensional collision with a stationary particle of mass m. They are in contat for brief time T. Their force of interaction increases from zero to `F_(0)` linearly inn time `T/2` and decreases linearly to zero in further time `T/2`. the magnitutde of `F_(0)` is

Options

A. `m u//T`
B. `2 m u//T`
C. `4 m u//T`
D. `m u//2T`

Answer

C

Explanation

Area under the force-time graph is impules, and impulse is change in momentum.
Area of graph=change in momentum
`implies 1/2 TF_(0)=2 m u implies F_(0)=(4m u)/(T)`.