A plumb bob of mass `1 kg` is hung from the ceiling of a train compartment.The train moves on an inclined plane with constant velocity. If the angle of inclined is `30^(@)`.Find the angle made by the string with the normal to the ceiling .Also ,Find the tension in the string `(g = 10 m//s^(2))`

Options

A. `30^(@)`
B. `tan^(-1)(2//sqrt(3))`
C. `tan^(-1)(sqrt(3)//2)`
D. `tan^(-1)(2)`

Answer

B

Explanation

`T sin theta-mg sin 30^(@)=ma`
`implies T sin theta =mg sin 30^(@)+mg//2` …(i)
`T cos theta=mg cos 30^(@)` …(ii)

Dividing Eqs. (i) by (ii), we get
`tan theta=(2)/(sqrt(3))`.