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A pendulum of mass m hangs from a suppor...

A pendulum of mass m hangs from a support fixed to a trolley. The direction of the string when the trolley rolls up a plane of inclination `alpha` with acceleration `a_(0)` is

A

`theta=tan^(-1)alpha`

B

`theta=tan^(1)((a_0)/(g))`

C

`theta=tan^(1)((g)/(a_0))`

D

`theta=tan^(1)((a_(0)+g sinalpha)/(g cos alpha))`

Text Solution

Verified by Experts

The correct Answer is:
D
As in fig.

`T sin theta =ma_(0)+mg sin alpha`
`T cos theta =mg cos alpha`
`tan theta=(a_(0)+g sin alpha)/(g cos theta)`.
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