A constant force `vecF=(3hati+2hatj+2hatk)` N acts on a particle displacing it from a position `vec(r_1)=(-hati+hatj-2hatk)m` to a new position `vecr_2=(hati-hatj+3hatk)m`. Find the work done by the force.

Explanation

To find the work done by the force \( \vec{F} = (3\hat{i} + 2\hat{j} + 2\hat{k}) \) N on a particle as it moves from position \( \vec{r_1} = (-\hat{i} + \hat{j} - 2\hat{k}) \) m to position \( \vec{r_2} = (\hat{i} - \hat{j} + 3\hat{k}) \) m, we can follow these steps:

### Step 1: Calculate the displacement vector \( \vec{R} \)
The displacement \( \vec{R} \) is given by the difference between the final and initial position vectors:
\[ \vec{R} = \vec{r_2} - \vec{r_1} \]

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