A force of `10N` is acting on a block of `20kg` on horizontal surface with coefficient of friction `mu=0.2`. Calculate the work done by the force.

Explanation

To solve the problem step by step, we need to analyze the forces acting on the block and determine whether it moves or not.

### Step 1: Identify the forces acting on the block.
- The applied force \( F = 10 \, \text{N} \) is acting horizontally.
- The weight of the block \( W = mg = 20 \, \text{kg} \times 10 \, \text{m/s}^2 = 200 \, \text{N} \) acts downwards.
- The normal force \( N \) acts upwards and is equal to the weight of the block in this case, so \( N = 200 \, \text{N} \).
- The frictional force \( f \) opposes the motion and is calculated using the coefficient of friction \( \mu \).

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