Home
Class 11
PHYSICS
A small body of mass m moving with veloc...

A small body of mass m moving with velocity `v_(0)` on rough horizontal surface, finally stops due to friction. Find, the mean power developed by the friction force during the motion of the body, if the frictional coefficient `mu`=0.27,m=1 kg and `v_(0)=1.5 ms^(-1)`.

Text Solution

Verified by Experts

`barP=1/Tunderset0oversetTintP*dt`
`=1/Tunderset0oversetTintmumg(v_0-mug t)dt` (numerically)
`(mumg)/(T)(v_0T-(mugT^2)/(2))`
`=mumg(v_0-(mugT)/(2))`
where `T=(v_0)/(mug)impliesbarP=(mumgv_0)/(2)=(0.27xx1xx9.8xx1.5)/(2)`
`implies barP=2.025W`
Promotional Banner

Topper's Solved these Questions

  • WORK, POWER & ENERGY

    CENGAGE PHYSICS ENGLISH|Exercise Solved Examples|15 Videos

  • WORK, POWER & ENERGY

    CENGAGE PHYSICS ENGLISH|Exercise Exercise 8.1|25 Videos

  • VECTORS

    CENGAGE PHYSICS ENGLISH|Exercise Exercise Multiple Correct|5 Videos

Similar Questions

Explore conceptually related problems

A small body of mass m is located on a horizontal plane at the point O. The body acquires a horizontal velocity v_0 . Find the mean power developed by the friction force during the whole time of motion, if the frictional coefficient mu=0.27 , m=1.0kg and v_0=1.5ms^-1 .

A body of mass 2 kg is kept on a rough horizontal surface as shown in the figure. If coefficient of friction is 0.5, find the work done by frictional force in the interval t=0 to t=5 sec

A block of mass m moving with a velocity v_(0) on a rough horizontal surface from x=0 coefficient of friction is given by mu=mu_(0)+ax . Find the kinetic energy of the block as function of x before it comes to rest.

A block of mass 5kg is lying on a rough horizontal surface. The coefficient of static and kinetic friction are 0.3 and 0.1 and g= 10 ms^(-2) The frictional force on the block is

A body of mass 2kg is placed on a horizontal surface having kinetic friction 0.4 and static friction 0.5 . If the force applied on the body is 2.5N , then the frictional force acting on the body will be

A ring of mass m sliding on a smooth surface with velocity v_(0) enters rough surface with coefficient of kinetic friction mu_(k) , then

If a body has kinetic energy. T, moving on a rough horizontal surface stops at distance y. The frictional force exerted on the body is

A block of mass m is moving on a rough horizontal surface. mu is the coefficient of kinetic friction between the block and the surface. What is the net force exerted by the surface on the block?

A body of mass 10 kg moves on rough horizontal surface with initial velocity 10m/s and travels 500m before coming to rest. The coefficient of friction is

A block of mass 10kg is placed on a rough horizontal surface having coefficient of friction mu=0.5 . If a horizontal force of 100N is acting on it, then acceleration of the will be.