There are two inclined planes with the same vertical height, but with different angles of inclination. Two bodies of mass m each are placed at the bottom of the inclined plane. Two external forces of equal magnitude do work in taking the bodies to the top of the inclined plane. Which force does more work?

Explanation

To solve the problem, we need to analyze the work done by the external forces on the two bodies as they move up the inclined planes. Here's a step-by-step solution:

### Step 1: Understand the Setup
We have two inclined planes with the same vertical height (h) but different angles of inclination (θ1 and θ2). The bodies of mass m are placed at the bottom of each inclined plane.

### Step 2: Identify the Displacement
For an inclined plane, the displacement (d) along the incline can be calculated using the relationship between the vertical height (h) and the angle of inclination (θ). The displacement along the incline can be expressed as:
\[ d = \frac{h}{\sin(\theta)} \]
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