A ring of mass m=10kg can slide through ...

A ring of mass `m=10kg` can slide through a vertical rod with friction. It is connected with a spring of force constant `k=100Nm^-1`. The relaxed length of spring is `4m`. The ring is displaced `3m` as shown in the figure and released. Find velocity of ring when spring becomes horizontal.

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`m=10kg`, `k=400Nm^-1`
Natural length of spring `=4m`
Decreasing in PE=increasing in KE
`1/2kxx1+mgh=1/2mv^2`
`1/2xx400xx1^2+10xx10xx3=1/2xx10v^2`
`200+300=5v^2impliesv=10ms^-1`

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