In the situation shown in figure all contact surfaces are smooth. The force constant of the spring is K. Two forces F are applied as shown. The maximum elongation produced in the spring is how many times of `F//K` (initially the spring is relaxed)?

Answer

`(2)`

Explanation

Maximum elongation is given by
`x_(max)=(2[F_1m_2+F_2m_1])/(K(m_1+m_2))`
Here `F_1=F_2=F`, `m_1=m` and `m_2=M`
Put the values and solve to get `x_(max)=2F//K`