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The arrangement shown in figure is at re...

The arrangement shown in figure is at rest. An ideal spring of natural length `l_0` having spring constant `k=220Nm^-1`, is connected to block A. Blocks A and B are connected by an ideal string passing through a friction less pulley. The mass of each block A and B is equal to `m=2kg` when the spring was in natural length, the whole system is given an acceleration `veca` as shown. If coefficient of friction of both surfaces is `mu=0.25`, then find the maximum extension in `10(m)` of the spring. `(g=10ms^-2)`.

Text Solution

Verified by Experts

The correct Answer is:
`(10)`
Let the maximum extension in spring be x.

Apply work-energy theorem: (Net work done by tension will be zero)
`-1/2kx^2-8x-7x+28x-2x=DeltaKE=0`
`implies -1/2xx220x^2+11x=0-x=0.1m=10cm`
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