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Six particles situated at the corners of a regular hexagon of side a move at a constant speed v. Each particle maintains a direction towards the particle at the next corner. Calculate the time the particles will take to meet each other.

A

`v/a`

B

`(2a)/v`

C

`(2a)/(v(2+sqrt(3)))`

D

`(2a)/(v(2-sqrt3))`

Text Solution

Verified by Experts

The correct Answer is:
D
d. `t = a/(v-vcospi/n). Here n = 12`

`rArr t = a/(v-vcos)(2pi/(12)) = (2a)/(v(2-sqrt3))`.
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