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Figure shows that particle A is projecte...

Figure shows that particle A is projected from point P with velocity u along the plane and simultaneously another particle B with velocity v at an angle `alpha` with vertical. The particles collide at point Q on the plane. Then

A

`v sin (alpha - theta_0) = u`

B

`v cos (alpha-theta_0) =u`

C

`v = u`

D

None of these

Text Solution

Verified by Experts

The correct Answer is:
A
a. If the particles collide at Q,
it means they travel same
displacement along the plane
in same time. So their velocity
components along the plane
should be same.

`v cos (beta+theta_0) = u`
and `beta = 90^@ - alpha`
Solve to get `v sin (alpha-theta_0) =u`.
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