Home
Class 11
PHYSICS
A uniform rod of length l is from rest s...

A uniform rod of length `l` is from rest such that it rotates about a smooth pivot. The angular speed of the rod when it becomes vertical is.
.

Text Solution

Verified by Experts

`/_\K+/_\U=0`
`(1/2I_(0)omega^(2)-0)+[-mgl/4]=0`……..i.
`I_(0)=(Ml^(2))/12+m(l/4)^(2)=7/48ml^(2)`….ii
From i andii `omega=2 sqrt((6g)/(7l))`
Promotional Banner

Topper's Solved these Questions

  • RIGID BODY DYNAMICS 2

    CENGAGE PHYSICS ENGLISH|Exercise Exercise 3.2|13 Videos

  • RIGID BODY DYNAMICS 2

    CENGAGE PHYSICS ENGLISH|Exercise Exercise 3.3|21 Videos

  • RIGID BODY DYNAMICS 2

    CENGAGE PHYSICS ENGLISH|Exercise Solved Examples|12 Videos

  • RIGID BODY DYNAMICS 1

    CENGAGE PHYSICS ENGLISH|Exercise Integer|11 Videos

  • SOUND WAVES AND DOPPLER EFFECT

    CENGAGE PHYSICS ENGLISH|Exercise Integer|16 Videos

Similar Questions

Explore conceptually related problems

A uniform disc of mass M and radius R is supported vertically by a pivot at its periphery as shown. A particle of mass M is fixed to the rim and raised to the highest point above the center. The system is released from rest and it can rotate about pivot freely. The angular speed of the system when the attached object is directly beneath the pivot, is

A uniform rod of length 50 cm is released in the vertical plane from the position shown in the figure. The rod is hinged smoothly at O. The angular speed of rod when it becomes horizontal is ( take g = 10m s^(-2) )

A rod of length L is hinged from one end. It is brought to a horizontal position and released. The angular velocity of the rod, when it is in vertical position, is

A uniform rod AB of length l and mass m is free to rotate about an Axis passing through A and perpendicular to length of the rod. The rod is released from rest as shown in figure. Given that the moment of inertia of the rod about A is (ml^(2))/3 The initial angular acceleration of the rod will be

A uniform rod of length L and mass m is free to rotate about a frictionless pivot at one end as shown in figure. The rod is held at rest in the horizontal position and a coin of mass m is placed at the free end. Now the rod is released The reaction on the coin immediately after the rod starts falling is

A uniform rod of mass m and length L lies radialy on a disc rotating with angular speed omega in a horizontal plane about vertical axis passing thorugh centre of disc. The rod does not slip on the disc and the centre of the rod is at a distance 2L from the centre of the disc. them the kinetic energy of the rod is

A uniform rod of mass m and length L is hinged about one end and can freely rotate in a vertical plane. The angular velocity of the rod, when it falls from position P to Q. through an angle alpha starting from rest, is

A uniform rod AB of length l and mass m is free to rotate about point A. The rod is released from rest in the horizontal position. Given that the moment of inertia of the rod about A is (ml^ 2 ) / ( 3 ) , the initial angular acceleration of the rod will be

A rod AB of mass m and length L is rotating in horizontal plane about one of its ends which is pivoted. The constant angular speed with which the rod is rotating is omega . The force applied on the rod by the pivot is

A uniform rod of length L is free to rotate in a vertical plane about a fixed horizontal axis through B . The rod begins rotating from rest. The angular velocity omega at angle theta is given as